Find the value of m so that only one value of x satisfies the equation:
4x^2 – 8x + m = 0
how i do dis?
all ive done is divide the whole equation by 4 to get
x^2 - 4x + m/4 = 0
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Algebra stuff.
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Algebra stuff.
by DoxC on Sun Mar 23, 2014 5:07 am
I know this isn't the place to be asking about algebra but ill ask anyway.
how i do dis?
all ive done is divide the whole equation by 4 to get
x^2 - 4x + m/4 = 0
how i do dis?
all ive done is divide the whole equation by 4 to get
x^2 - 4x + m/4 = 0
- DoxC
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Re: Algebra stuff.
by Vicpop on Sun Mar 23, 2014 5:23 am
look at the quadratic formula. the only way you can have it so that you get one solution is if sqrt(b^2 - 4ac) = 0, that is b^2-4ac = 0. hope this helps
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Re: Algebra stuff.
by DoxC on Sun Mar 23, 2014 5:28 am
oh now i get it, so the discriminant was what is should have looked for
thanks Vicpop
thanks Vicpop
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Re: Algebra stuff.
by kaya67 on Mon Oct 20, 2014 9:17 am
Happy that the site is still running, let alone popular 
kaya
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